Question 559373
legs of traingle are equal
let them be x each

pythagoras theorem

x^2+x^2=6^2
2x^2=36
/2
x^2=18
{{{x= sqrt(18)}}}

The perimeter = {{{ sqrt(18)+sqrt(18)+6}}}

={{{3sqrt(2) +3sqrt(2)+6}}}

= {{{6sqrt(2)+6}}}

={{{6(sqrt(2)+1)}}}

m.ananth@hotmail.ca