Question 559361
(2x+5)(6x-1)=120

2x(6x-1)+5(6x-1)=120

12x^2-2x+30x-5=120
12x^2+28x-5-120=0
12x^2+28x-125=0

Find the roots of the equation by quadratic formula								
								
a=	12	,	b=	28	,	c=	-25	
								
b^2-4ac=	784	+	1200					
b^2-4ac=	1984	
{{{	sqrt(	1984	)=	44.54	}}}
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	-28	+	44.54	)/	24			
x1=	0.69							
x2=(	-28	-44.54	) /	24				
x2= 	-3.02