Question 559201
ONE WAY
You could do it by writing the equation of the line in point-slope form, using the coordinates of the point given:
{{{y-(-5)=-4(x-2)}}} 
and then you could work with it to transform it into an equivalent expression that looks more elegant, like this:
{{{y-(-5)=-4(x-2)}}} --> {{{y+5=-4x+8}}} --> {{{y=-4x+8-5}}} --> {{{y=-4x+3}}}
or {{{y-(-5)=-4(x-2)}}} --> {{{y+5=-4x+8}}} --> {{{4x+y+5=8}}} --> {{{4x+y=3}}}
ANOTHER WAY
You could also write the slope-intercept form of a line with slope {{{-4}}} as
{{{y=-4x+b}}} and find {{{b}}} by substituting the coordinates of the point and solving for {{{b}}}
{{{-5=-4*2+b}}} --> {{{-5=-8+b}}} --> {{{-5+8=b}}} --> {{{b=3}}}
So you get {{{y=-4x+3}}}.