Question 559026
find the domain of f(x)=(16x+3)/(x^2+6x-72)
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The domain is all values of x for which the function is defined.
The function will be defined for all values in which the denominator does not equal 0.
The denominator can be factored as 
(x^2+6x-72) = (x-6)(x+12)
So the domain is all real numbers except x=6, x=-12
The graph is below:
{{{graph(300,300,-15,15,-10,10,(16x+3)/(x^2+6x-72))}}}