Question 558823
A gas station has a 7% chance of running out of gas. 
a)What is the probability the gas station will run out of gas one day in the next two weeks?
P(x = 1) = 14C1*0.07*0.93^13 = binompdf(14,0.07,1) = 0.3815
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b)What is the probability the gas station will run out of gas at least two days in the next two weeks?
P(2<= x <=14) = 1 - binomcdf(14,0.07,1) = 0.2564
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c)What is the expected number of times the gas station will run out of gas
in two weeks?
Expected value = np = 14*0.07 = 0.98 = 1 day
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Cheers,
Stan H.
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