Question 558843
Your problem is:
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{{{((5*(-1+5y))/(-4))-7y = 8}}}
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and it likely has an error with one of the signs because solving this problem does not lead to 3y = -27.
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Here's my work:
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You can eliminate the denominator on the left side by multiplying both sides of this equation (all terms) by -4. 
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When you do that multiplication the problem becomes:
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{{{((-4)*5*(-1+5y))/((-4))-7y*(-4) = 8*(-4)}}}
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On the left side, cancel the denominator with the common factor in the numerator as shown:
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{{{((cross(-4))*5*(-1+5y))/(cross((-4)))-7y*(-4) = 8*(-4)}}}
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and you are left with:
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{{{5*(-1+5y)-7y*(-4)= 8*(-4)}}}
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On the left side, do the distributed multiplication by multiplying the constant 5 times each of the terms in the parentheses to get:
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{{{-5 + 25y -7y*(-4)= 8*(-4)}}}
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On the left side multiply the -7y times the -4 to get +28y and on the right side multiply the 8 times the -4 to get -32. This results in the equation becoming:
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{{{-5 + 25y +28y= -32}}}
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get rid of the -5 on the left side by adding +5 to both sides as follows:
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{{{+5 - 5 + 25y = +5 - 32 }}}
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On the left side the +5 and -5 cancel out and on the right side the +5 and the -32 combine to give -27. As a result you are left with:
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{{{25y + 28y = -32}}}
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Combine the two terms on the left side and you get:
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{{{53y = -32}}}
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This obviously is not the answer you were looking forward. I expect that your problem has a sign error because if you had arrived at:
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{{{-25y + 28y = -32}}}
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the result would be:
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{{{3y = -32}}}
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and that would be what you were expecting.
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Maybe your original problem should have had a negative sign in the factor:
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{{{(-1+5y)}}}
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so that it was {{{-1 -5y}}}instead.
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I hope this helps you to find where the error is. If it doesn't please post the problem again and maybe another tutor can find what is wrong here.
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