Question 558732
Start with the function for the height, as a function of time, (h(t), of an object propelled upwards from an initial height of {{{h[0]}}} with an initial velocity of {{{v[0]}}}. 
{{{h(t) = -(1/2)gt^2+v[0]t+h[0]}}} where: g (acceleration due to gravity) = 32ft/sec.squared.
{{{h(t) = -16t^2+v[0]t=h[0]}}} Substitute: {{{v[0] = 32}}} and {{{h[0] = 4}}}.
{{{h(t) = -16t^2+32t+4}}} Note that the negative comes from the fact that gravity is acting downward.