<PRE><B>Question 558697</B>
(y+1)^(2)=-8(x-3)
vertex: ?
focus point: ?
equation of the axis of symmetry: ?
equation of directrix: ?
2 random points on equation: ? 
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Rearrange the equation:
-8x+24 = (y+1)^2
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-8x = (y+1)^2 - 24

x = (-1/8)(y+1)^2 + 3
This is a parabola opening to the left.
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vertex: (3,-1)
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focus point:
4p = -1/8
p = -1/32
focus: (3-(1/32),-1)
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equation of the axis of symmetry: y = -1
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equation of directrix: x = 3+(1/32)
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2 random points on equation:  
-8x+24 = (y+1)^2
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Let x = 1, then (y+1)^2 = 16, then y =3 or y = -6
Let x = 5/2, then (y+1)^2 = 4, then y = 1 or y = -3
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Cheers,
Stan H.
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