Question 558413
Solve.
 (64)16^(-3x)=16^(3x-2)
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If you mean:

{{{64*16^(-3x)=16^(3x-2)}}}
Multiply by 16^(3x)
{{{64 = 16^(6x-2)}}}
{{{4^3 = 4^(12x-4)}}}
12x - 4 = 3
x = 7/12