Question 1200
Sol: (i) Assume the time if he drives on the interstate is x hrs,then it takes x+2
         for him to drive on highway.
         Since both routes are the same length,we have
           50x = 30(x+2)
         or 50x = 30x + 60,
         or 20 x = 60, so x = 3 (hrs)
         Hence,the required distance is 50*3= 150 miles.
    (ii) Assume the dimensions are L& W,we have
         2L+ 2 W = 300 or L + W = 150...(1)
         and LW = 500...(2)
         By (1): L = 150-W, in (2),replace L by 150-W,we have
         (150 - W)W = 500,
         So, W^2 -150 W + 500 = 0,
         By quadratic formula,we obtain W= 75+ 5sqrt(205) =146.59
         or  75- 5sqrt(205) = 3.41.
         And so,we have the correponding 
         L= 150 -W = 150-(75+ 5sqrt(205)) = 75- 5sqrt(205)
         or L= 150 -W = 150-(75 - 5sqrt(205)) = 75 + 5sqrt(205)
  Answer: the dimensions of the rectangle are 75- 5sqrt(205) and 75+ 5sqrt(205)