Question 558261
<pre>
Let N be the number of apples

{{{(matrix(5,1, all, of,the,N, apples))}}}-{{{(matrix(9,1, 1/3,of,the, N, apples,for, the, first, person))}}}-{{{(matrix(9,1, 1/4,of,the, N, apples,for, the, second, person))}}}-{{{(matrix(9,1, 1/8,of,the, N, apples,for, the, third, person))}}}-{{{(matrix(9,1, 1/5,of,the, N, apples,for, the, fourth, person))}}}-{{{(matrix(6,1, ten, apples,for, the, fifth, person))}}} = {{{(matrix(6,1, one, apple,for, the, sixth, person))}}}


                    N - {{{1/3}}}N - {{{1/4}}}N - {{{1/8}}}N - {{{1/5}}}N - 10 = 1 

Add 10 to both sides

                         N - {{{1/3}}}N - {{{1/4}}}N - {{{1/8}}}N - {{{1/5}}}N = 11 

Multiply every term by 120:

    120·N - 120·{{{1/3}}}N - 120·{{{1/4}}}N - 120·{{{1/8}}}N - 120·{{{1/5}}}N = 120·11 

                  120N - 40N - 30N - 15N - 24N =  1320 

                                           11N = 1320
                                          
                                             N = {{{1320/11}}}
                                              
                                             N = 120

Answer = 120 apples.

Edwin</pre>