Question 53808
I am supposed to find the imaginary solution to the following equation and check my answer. 9x^2-6x+4=0 So far I have: 
x=(6+/- sqrt(6)^2-4(9)(4))/18
x=(6+/- sqrt-108)/18
x= (6+/- 6i sqrt3)/18
x=(1+/- i sqrt3)/3 
This does not check where did I go wrong?

solun: 9x^2-6x+4 = 0
x = (-(-6)+ - sqrt((-6)^2-4*9*4))/(2*9)
  = (6 + - sqrt(36 - 4 * 36 ))/18
  = (6 + - (6 * (sqrt(-3))))/18                 since sqrt(-1) = i
  = (1+i sqrt(3)/3 or 3(1-i sqrt(3))/3          hence sqrt(-3) = i sqrt(3)