Question 558183
ln(x/(x-1))+ln((x+1)/x)-ln(x^2-1)
{{{(x/(x-1))*((x+1)/x)/ (x^2-1) }}}
= {{{((x-1)/(x+1))/((x+1)(x-1))}}}
= {{{((x-1)/(x+1))* (1/((x+1)(x-1)))}}}
={{{ln(1/(x+1)^2)}}}