<PRE><B>Question 558078</B>
Armond has two solutions available in the lab, one with 5% alcohol and another with 13% alcohol. How much of each solution should he mix together to obtain 6 gallons of a solution that contains 8% alcohol. 
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alcohol + alcohol = alcohol
0.06x + 0.13(6-x) = 0.08*6
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Multiply thru by 100 to get:
6x + 13*6 - 13x = 8*6
-7x = -5*6
x = 30/7
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x = 4 2/7 gallons (amt. of 6% solution)
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6-x = 1 5/7 gallons (amt. of 13% solution)
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Cheers,
Stan H.
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