Question 557691
ln(x+2)-ln(x-1)=1
ln[x+2)/(x-1)]=1
convert to exponential form: base(e) raised to log of number(1)=number([x+2)/(x-1)])
e^1=[x+2)/(x-1)]=e
e(x-1)=x+2
ex-e=x+2
ex-x=e+2
x(e-1)=e+2
x=(e+2)/(e-1)
e≈2.71828..