Question 557408
{{{13/(33r) + 11/(9r)}}}
just like in ordinary fractions, you have to have a common denominator to add (or subtract) fractions.
In this problem the common denominator will be 99r
:
{{{(3(13)+11(11))/(99r)}}} = {{{(39+121)/(99r)}}} = {{{160/(99r)}}}