Question 557670
{{{ log( 4,(x^2-3) ) }}} + {{{log( 4,10 ) = 1 }}}
Make the substitution:
{{{ log( 4,4 ) = 1 }}}
{{{ log( 4,(x^2-3) ) }}} + {{{log( 4,10 ) = log( 4,4 ) }}}
{{{ log( 4, 10*(x^2 - 3) ) = log( 4,4 ) }}}
{{{ 10*( x^2 - 3 ) = 4 }}}
{{{ 10x^2 - 30  = 4 }}}
{{{ 10x^2 = 34 }}}
{{{ x^2 = 3.4 }}}
{{{ x = 1.844 }}}
check answer:
{{{ log( 4,(3.4-3) ) }}} + {{{log( 4,10 ) = 1 }}}
{{{ log(4, .4 ) + log( 4, 10 ) = 1 }}}
{{{ log( 4, (.4*10) ) = 1 }}}
{{{ log( 4,4 ) = 1 }}}
OK