Question 557464

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-4,8\right)]. So this means that {{{x[1]=-4}}} and {{{y[1]=8}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(7,-14\right)].  So this means that {{{x[2]=7}}} and {{{y[2]=-14}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-14-8)/(7--4)}}} Plug in {{{y[2]=-14}}}, {{{y[1]=8}}}, {{{x[2]=7}}}, and {{{x[1]=-4}}}



{{{m=(-22)/(7--4)}}} Subtract {{{8}}} from {{{-14}}} to get {{{-22}}}



{{{m=(-22)/(11)}}} Subtract {{{-4}}} from {{{7}}} to get {{{11}}}



{{{m=-2}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-4,8\right)] and *[Tex \LARGE \left(7,-14\right)] is {{{m=-2}}}


<b><font size=4>If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com">jim_thompson5910@hotmail.com</a>


Also, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Thank you


Jim</font></b>