<PRE><B>Question 557276</B>
find the roots of the polynomial equation:x^3-2x^2+10x+136=0
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I graph the cubic and found a zero at x = -4
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Using synthetic division, find the other zeros:
-4)....1....-2....10....136
........1....-6....34...|..0
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Quotient: x^2-6x+34
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Find the zeros of the quotient:
x = [6 +- sqrt(6^2-4*34)]/2
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x = [6 +- sqrt(36-136)]/2
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x = [6 +- sqrt(-100)]/2
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x = [2 +- 5i]
x = 2+5i or x = 2 - 5i or -4
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Cheers,
Stan H.
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