Question 557237
find the inverse: 
y=6+log(base 2)^x
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1st: Interchange x and y:
x = 6 + log2(sqrt(y))
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2nd: solve for "y":
log2(sqrt(y)) = x-6
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sqrt(y) = 2^(x-6)
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y = 2^(2x-12)
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y = 2^(2x)/2^12
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Cheers,
Stan H.
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