<PRE><B>Question 557193</B>
In a batch of 400 pieces, 10 are defective. 20 pieces are randomly chosen. What is the probability that no more than 6 pieces are defective? What is the probability that 0 pieces are defective?
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Binomial Problem with n = 20 and p(defective) = 1/40
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P(0&lt;= x &lt;= 6) = binomcdf(20,1/40,6) = 0.9999
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P(x = 0) = 20C0(1/40)^0*(39/40)^20 = (39/40)^20 = 0.6027
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Cheers,
Stan H.
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