Question 557154
 Passing through (-8,-6) and parallel to the line whose equation is y=-5x+1.
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The given line has a slope = -5.
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(y--6) = -5(x--8)
y +6 = -5(x+8)
y = -5x-46
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Write an equation for the line in point-slope form y +6 = -5(x+8). Write an equation for the slope-intercept form y = -5x-46.

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Cheers,
Stan H.
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