Question 557140
Find an expression for the area of a triangle with base (4a+3) and perpendicular height (6a-2)
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Area = (1/2)(base)(height)
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A = (1/2)(6a-2)(4a+3)
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A = (3a-1)(4a+3)
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A = 12a^2+9a-4a-3
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A = 12a^2+5a-3
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Cheers,
Stan H.
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