Question 557067
Write an equation for each statement
:
Ki has $5.10 in nickels, dimes, and quarters.
.05n + .10d + .25q = 5.10
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 He has an equal number of dimes and nickels,
d = n
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with the value of the quarters being $2.40 more than the total value of the dimes and nickels.
.25q - (.05n + .10d) = 2.40
d = n, replace n with d
.25q - (.05d + .10d) = 2.40
.25q - .15d = 2.40
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Back to the 1st equation, replace n with d there too, subtract the above equ
.05d + .10d + .25q = 5.10
:
+.15d + .25q = 5.10
-.15d +.25q = 2.40
------------------- subtraction eliminates q, find d
.30d = 2.70
d = {{{2.70/.30}}}
d = 9 dimes
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You can confirm this solutions by finding the no. of nickels (9) and quarters and the value thereof.