Question 554364
if the terminal side of θ is in quadrant 2 and sinθ=12/13 then how do you find:
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In quadrant 2:
sin θ=12/13
cos θ=5/13
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sin(π-θ)=12/13 (reference angle in quadrant I where sin>0)
sin(&#960;+&#952;)=-12/13  (reference angle in quadrant IV where sin<0)
cos&#952;=-5/13  (reference angle in quadrant II where cos<0)
cos(&#960;/2-&#952;)=sin &#952;=-12/13 (reference angle in quadrant IV where sin<0)
sin-&#952;=-12/13 (reference angle in quadrant III where sin<0)
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note: assume &#952; is an angle between &#960; and &#960;/2 (quadrant II), then move it accordingly)