Question 556787
ind all solutions in [0, 2pi) to the equation 2sin(2theta)= - square root of 3
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use x in place of theta
2sin2x=-&#8730;3
sin2x=-&#8730;3/2
2x=4&#960;/3 and 5&#960;/3 (in quadrants III and IV where sin<0
x=2&#960;/3 and 5&#960;/6