<PRE><B>Question 556439</B>
If the 3-digit positive integer is abc, then


*[tex \LARGE 100a + 10b + c = 11(a+b+c) = 11a + 11b + 11c]


*[tex \LARGE 89a = b + 10c]


If a = 1, then b = 9 and c = 8 and we have the number 198. If a is larger than 1, then we cannot have integer values b and c that satisfy (since b and c are less than 10). Hence the only integer is 189.</PRE>