Question 555587
Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need?
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As I told you two days ago, you have to know the confidence level
for your problem because:
n = [z/E]^2*pq
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If the confidence level is 95%, then z = 1.96
Since you have no p-value you use p = 1/2 = q
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Then you would get:
n = [1.96/0.02]^2*(1/2)(1/2) = 2401
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Cheers,
Stan H.
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