Question 555483


This equation is difficult. I have tried this expression six times and the answer is wrong still. I need help.
1/x-3 + 2/x+3 = -5x/x^2-9
(x^2-9)1/x-3 + (x^2-9)2/x+3
(x^2-9)-5x/x^2-9
or (x+3)*1+(x-3)*2=-5x
1x+3+2x-6=-5x
8x=3
x=3/8
 My question is how to arrive at 8x=3? Show steps how to add or multiply or subtract to get 8x. I can do the expression until I get to this point. I do not understand how to simplify and expand to get the answer.


{{{1/(x-3) + 2/(x+3) = (-5x)/(x^2-9)}}}


{{{1/(x-3) + 2/(x+3) = (-5x)/(x - 3)(x + 3)cross((x^2-9))}}} ---- factoring denominator {{{x^2 - 9}}}


1(x + 3) + 2(x - 3) = - 5x --- Multiplying entire equation by LCD, (x - 3)(x + 3)


x + 3 + 2x - 6 = - 5x


3x - 3 = - 5x


3x + 5x = 3


8x = 3


x = {{{highlight_green(3/8)}}}  


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