Question 555487
You really should give us a hint of what you would like to do with this expression!
Did you want to factor it?
{{{x^3-8/27}}} This is a difference of cubes.
{{{(x)^3-(2/3)^3}}} which will factor nicely thus:
{{{A^3-B^3 = (A-B)(A^2+AB+B^2)}}} and in this case, {{{A = x}}} and {{{B = 2/3}}} so we have:
{{{x^3-8/27 = (x-2/3)(x^2+(2/3)x+4/9)}}}