Question 555283


{{{(3x-2y)^2}}} Start with the given expression.



{{{(3x-2y)(3x-2y)}}} Expand. Remember something like {{{x^2=x*x}}}.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3x)-2y)(highlight(3x)-2y)}}} Multiply the <font color="red">F</font>irst terms:{{{(3*x)*(3*x)=9*x^2}}}.



{{{(highlight(3x)-2y)(3x+highlight(-2y))}}} Multiply the <font color="red">O</font>uter terms:{{{(3*x)*(-2*y)=-6*y*x}}}.



{{{(3x+highlight(-2y))(highlight(3x)-2y)}}} Multiply the <font color="red">I</font>nner terms:{{{(-2*y)*(3*x)=-6*y*x}}}.



{{{(3x+highlight(-2y))(3x+highlight(-2y))}}} Multiply the <font color="red">L</font>ast terms:{{{(-2*y)*(-2*y)=4*y^2}}}.



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So we have the terms: {{{9*x^2}}}, {{{-6*y*x}}}, {{{-6*y*x}}}, {{{4*y^2}}} 



{{{9*x^2-6*y*x-6*y*x+4*y^2}}} Now add every term listed above to make a single expression.



{{{9x^2-12yx+4y^2}}} Now combine like terms.



So {{{(3x-2y)^2}}} FOILs to {{{9x^2-12yx+4y^2}}}.



In other words, {{{(3x-2y)^2=9x^2-12yx+4y^2}}}.


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