Question 555266
x(x+30)=4000


x^2+30x=4000


x^2+30x-4000=0



Now use the quadratic formula to solve:


x = (-b+-sqrt(b^2-4ac))/(2a)


x = (-(30)+-sqrt((30)^2-4(1)(-4000)))/(2(1))


x = (-30+-sqrt(900-(-16000)))/(2)


x = (-30+-sqrt(16900))/2


x = (-30+sqrt(16900))/2 or x = (-30-sqrt(16900))/2


x = (-30+130)/2 or x = (-30-130)/2


x = 100/2 or x = -160/2


x = 50 or x = -80



Ignore the negative solution. So the dimensions are 50 by 80 pixels.


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