Question 555082
Based on the lesson, which of the following would be the best approach for solving this system by substitution?

5x = y + 6
2x - 3y = 4 
Isolating the x value from the 5 by dividing it like this
5x=y+6
/5.  /5. /5
x=1/5y+6/5
2x-3y=4
2(1/5y+6/5)-3y=4
2/5y+12/5-3y=4
Now collect like terms -3y+2/5y
-13/5y+12/5=4
           -12/5.  -12/5
-13/5y=8/5
Isolate the y
-13/5y=8/5
/(-13/5). /(-13/5)
y=-.6153846151. However we need to convert this into a fraction to get x so Math Fract
Y=-8/13
Now substitute it into the original equation
2x-3y=4
2x-3(-8/13)=4
Again can't have a decimal so math Fract 
2x+24/13=4
Isolate 2x from -24/13 by adding 24/13 to 4
2x+24/13=4
    -24/13. -24/13
Again math Fract 
2x=28/13
Divide by 2
 2x=(28/13)
/2.    /2
Math Fract
x=14/13
CHECK
2x-3y=4
2(14/13)-3(-8/13)=4
4=4
Left hand side = Right hand side
Solution=(14/13,-8/13)