Question 554988
={{{(4b^2-3b)(5b^2)/(40b^3-30b^2)}}}
={{{(4b-3)(b)(5b^2)/(10b^2)(4b-3)}}}
={{{(4b-3)(5b^3)/(10b^2)(4b-3)}}}
={{{cross((4b-3))cross(5b^3)/cross((10b^2))cross((4b-3))}}}
={{{b/2}}}