Question 554791
{{{(4+3i)*(2-5i)}}} Start with the given expression.



{{{(4)(2)+(4)(-5i)+(3i)(2)+(3i)(-5i)}}} FOIL.



{{{8-20i+6i-15i^2}}} Multiply.



{{{8-20i+6i-15(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{8-20i+6i+15}}} Multiply.



{{{23-14i}}} Combine like terms.



So {{{(4+3i)*(2-5i)=23-14i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=23}}} and {{{b=-14}}}



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