Question 554746
{{{abs(2c+5)=21}}} Start with the given equation



Break up the absolute value (remember, if you have {{{abs(x)=a}}}, then {{{x=-a}}} or {{{x=a}}})


{{{2c+5=-21}}} or {{{2c+5=21}}} Set the expression {{{2c+5}}} equal to the original value 21 and it's opposite -21





Now lets focus on the first equation  {{{2c+5=-21}}}



{{{2c=-21-5}}}Subtract 5 from both sides



{{{2c=-26}}} Combine like terms on the right side



{{{c=(-26)/(2)}}} Divide both sides by 2 to isolate c




{{{c=-13}}} Divide





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Now lets focus on the second equation {{{2c+5=21}}}




{{{2c=21-5}}}Subtract 5 from both sides



{{{2c=16}}} Combine like terms on the right side



{{{c=(16)/(2)}}} Divide both sides by 2 to isolate c




{{{c=8}}} Divide






So the solutions to {{{abs(2c+5)=21}}} are:


{{{c=-13}}} or {{{c=8}}}



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