Question 554548
<pre>
x² - 3x - 1 = 0 (a=1, b=-3 and c=-1

x = {{{(-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

x = {{{(-(-3) +- sqrt( (-3)^2-4*(1)*(-1) ))/(2*(1)) }}}

x = {{{(3 +- sqrt(9+4 ))/2 }}}

x = {{{(3 +- sqrt(13))/2 }}}


Two solutions,

x = {{{(3 + sqrt(13))/2 }}} and x = {{{(3 - sqrt(13))/2 }}}

------------------------------
4x² + x - 1 = 0 (a=4, b=1, and c=-1

x = {{{(-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

x = {{{(-(1) +- sqrt( (1)^2-4*(4)*(-1) ))/(2*(4)) }}}

x = {{{(-1 +- sqrt(1+16 ))/8 }}}

x = {{{(-1 +- sqrt(17))/8 }}}


Two solutions,

x = {{{(-1 + sqrt(17))/8 }}} and x = {{{(-1 - sqrt(17))/8 }}}


Edwin</pre>