<PRE><B>Question 554491</B>
your equation looks like it should be:
s = 2*sqrt(5x)
s = the speed of the car in miles per hour.
x = the length of the skid in feet.
when x = 61.5 feet, then:&quot;
s = 2*sqrt(5*61.5) = 35.071 miles per hour
when x = 320 feet:
s = 2*sqrt(5*320) = 80 miles per hour.
a car traveling at 70 miles per hour would leave a skid mark as described in the following equation:
70 = 2*sqrt(5x)
divide this equation by 2 to get:
35 = sqrt(5x)
square both sides of this equation to get:
1225 = 5x
divide both sides of this equation by 5 to get:
x = 245 feet.
a car traveling at 70 miles per hour would leave a skid mark of 245 feet.
this assumes that it would skid to a stop without hitting anything.
if it hit something before coming to a stop, then the skid marks would be less than 245 feet.
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