Question 554416
Let
1st  Interger = x+1
2nd  Interger = x+3
3rd  Interger = x+5



Given
The sum of three consecutive odd integers is greater than 30
x+1+x+2+x+3>30
3x+6>30
3x>30-6
3x>24
3x/3>24/3
x>8


1st  Interger = x+1 = 8+1 = 9
2nd  Interger = x+3 = 8+3 = 11 
3rd  Interger = x+5 = 8+5 = 13