<PRE><B>Question 554392</B>
Let
Youngest brother age = x+2
Younger brother age = x+4
Oldest brother age = x+6


Given
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Three times the age of the youngest brother exceeds the oldest brothers age by 48 years

3(x+2)=x+6+48
3x+6=x+54
3x-x=54-6
2x=48
2x/2=48/2
x=24



Youngest brother age = x+2 = 24+2 = 26 years old
Younger brother age = x+4 = 24+4 = 28 years old
Oldest brother age = x+6 = 24+6 = 30 years old



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