Question 554328
let x and y are the numbers.
then
x*y= 56
and x-y= 8
x= 8+y
so,

(8+y)y = 56
so,
{{{y^2 +8y -56 =0}}}
y= {{{ (-8+- sqrt(8^2 - 4*1*(-56)))/2}}}
y= {{{ (-8+- sqrt(288))/2 }}}
y= {{{ -4+- 6sqrt(2) }}}
so, numbers are -4 + 6sqrt(2) and 4+6sqrt(2)