Question 554180
x^2+13x+40<5
        -5-5
x^2+13x+40-5<0
x^2+13x+35<0
 put the equation into the quadratic formula
{{{x = (-13) +- sqrt( 13^2-4*1*35 ))/(2*1) }}}
{{{x = (-13) +- sqrt(29))/(2)}}}
The discriminant=29 which means there are two solutions since it is greater than zero. 
x1=-13+sqrt29/(2)
x1=-3.80741759643275 
x2=-13-sqrt29/(2)
x2=-9.19258240356725
     -9.19258240356725 < x < -3.80741759643275 


 

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