Question 553680
if I have a triangle where the top angle is 50 degrees, how far will the two sides be so that the bottom of the triangle is 70 inches long?
:
We know the two other angles will be {{{(180-50)/2}}} = 65 degrees angles B & C
:
Using the law of sines where A=50 degrees, a = 70 inches, find b or c
{{{sin(A)/a}}} = {{{sin(B)/b}}}
{{{sin(50)/70}}} = {{{sin(65)/b}}}
{{{.766/70}}} = {{{.9063/b}}}
Cross multiply
.766b = 70 * .9063
.766b = 63.44
b = {{{63.44/.766}}}
b = 82.8 ~ 83 inches, the length of the two sides, the ends will be 70 inches apart