Question 553145


{{{3x-9y=27}}} Start with the given equation.



{{{-9y=27-3x}}} Subtract {{{3x}}} from both sides.



{{{-9y=-3x+27}}} Rearrange the terms.



{{{y=(-3x+27)/(-9)}}} Divide both sides by {{{-9}}} to isolate y.



{{{y=((-3)/(-9))x+(27)/(-9)}}} Break up the fraction.



{{{y=(1/3)x-3}}} Reduce.



So the equation {{{y=(1/3)x-3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=1/3}}} and the y-intercept is {{{b=-3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-3\right)]



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