Question 553144
Use the distance formula



d = sqrt((x2-x1)^2+(y2-y1)^2)



Remember that the two generic points are (x1, y1) and (x2, y2)

So (x1, y1) = (-3, -4), which means x1=-3 and y1=-4

and (x2, y2) = (-1, -2), which means x2=-1 and y2=-2


So in short, x1=-3, y1=-4, x2=-1, and y2=-2.


-------------------



d = sqrt((x2-x1)^2+(y2-y1)^2)



d = sqrt((-1-(-3))^2+(-2-(-4))^2)



d = sqrt((-1+3)^2+(-2+4)^2)



d = sqrt((2)^2+(2)^2)



d = sqrt(4+4)



d = sqrt(8)



d = 2*sqrt(2)



d = 2.8284271247462




So exact distance between the two points is approximately 2.8  units.