<PRE><B>Question 552976</B>
A store has six different fitness magazines and three different news magazines. If a customer buys three magazines at random, find the probability that the customer will select 2 fitness magazines and 1 news magazine. Please I need help with this question thank you.
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# of ways to pick 2 fitness mags: 6C2 = 15
# of ways to pick 1 news mag: 3C1 = 3
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Total # of ways to pick 2 fit and 1 news = 15*3 = 45
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# of ways to randomly pick 3 mags: 9C3 = 84
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P(2 fit and 1 news) = 45/84 = 0.5357
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Cheers,
Stan H.
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