Question 553044
{{{(2x^3-7x^2-17x-3)/(2x+3)}}}
Set your paper up like a long division problem
           
2x+3)   2x^3-7x^2-17x-3

look at your highest power first. 

What can I multiply 2x by to get 2x^3?

I can multiply by x^2

So I multiply by x^2 and get 2x^3+3x^2 and I subtract that from 2x^3+3x^2 and get -10x^2 and bring down the -17x

Now looking at -10x^2-17x, what can I multiply 2x by to get -10x^2? -5x

So I multiply by -5x and get -10x^2-15x. Since I'm subtracting and have a negative I reverse the signs and get -2x and bring down the -3

To get -2x-3 I multiply by -1 and get -2x-3 so again, reverse the signs and that all works out evenly

I get x^2-5x-1 as my answer.

This would be easier to diagram out for you, but hopefully this helped. You can also watch this video on dividing polynomials: http://www.khanacademy.org/video/polynomial-division?playlist=ck12.org+Algebra+1+Examples