Question 552957
<pre>
2x² + 12x + 15 = 0

Compare to

ax² + bx + c = 0

a=2, b=12, c=15

Substitute in

x = {{{(-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

x = {{{(-(12) +- sqrt( (12)^2-4*(2)*(15) ))/(2*(2)) }}}

x = {{{(-12 +- sqrt(144-120 ))/4 }}}

x = {{{(-12 +- sqrt(24))/4 }}}

x = {{{(-12 +- sqrt(4*6))/4 }}}

x = {{{(-12 +- 2*sqrt(6))/4 }}}

x = {{{(2(-6 +- sqrt(6)))/4 }}}

x = {{{(-6 +- sqrt(6))/2 }}}

Two solutions: {{{(-6 + sqrt(6))/2 }}} and {{{(-6 - sqrt(6))/2 }}}

Edwin</pre>