Question 552874
Please help me solve this graphing quad.
y=-1/2x2-4x-12 
Y + negative half x squared minus 4x minus 12
**
y=(-1/2)x^2-4x-12
complete the square
y=-1/2(x^2+8x+16)-12+8
y=-1/2(x+4)^2-4
This equation is that of a parabola which opens downward. Its standard form: y=-A(x-h)^+k, with (h,k) being the (x,y) coordinates of the vertex.
For given equation:
A=-1/2
vertex: (-4,-4)
See graph below as a visual check:
y=-.5(x+4)^2-4

{{{ graph( 300, 300, -10, 10, -10, 10,-.5(x+4)^2-4) }}}