Question 552701
{{{(b^4)^6*(b^2)^4}}} First multiply the exponents inside the parentheses by the appropriate exponents on the outside.
{{{(b^4)^6 = b^24}}} and {{{(b^2)^4 = b^8}}} so now you have:
{{{b^24*b^8}}} Now you add the exponents since the base is the same (that's b) and you are multiplying the two factors.
{{{b^(24+8) = b^32}}}